Demo Equipment

Demo: Force between two wires

Observations
  • The wires seem to twitch away from each other.
  • The wires must be exerting a small, repulsive force on each other.
Explanation of force direction
  • Imagine the left wire creates a B field. The current in the right wire experiences the B field.
  • B field due to left wire, at right wire, is out of page.
  • Force experienced by right wire = to right.
  • Repeat to find force on left wire.
Explanation of magnitude
  • r = 0.002 m
  • I = 1.5 A for both wires
  • L ~ 0.10 m
  • B = μ0 I / (2 π r) = 1.5×10-4 T, for field at right wire due to left wire.
  • F = B I L sin(θ) = 2.25×10-5 N

Notes: Velocity selector

Set up
  • A source of charged particles on the left.
  • Charged particles first pass through a narrow opening.
  • Then, they experience a downwards E field.
  • + are deflected down, - are deflected up
  • IF a B field into the board also fills the region, it by itself would deflect + up, - down.
  • FE = q E
  • FB = q v B
  • An aperture on the right blocks all particles except those which are not deflected.
  • The particles MUST have v = E / B
Questions
  • If a + charge goes too slowly, which way will it be deflected? FE (down) > FB (up) → it is deflected down.
  • If a - charge goes too fast, which way will it be deflected? FE (up) < FB (down) → down
Purpose
  • E and B fields can be easily and precisely created (capacitor, solenoid)
  • By controlling E and B, you can guarantee that the particles from a source have the same well known velocity.

Example: Velocity selector

Solution
  • v = E / B = 1200 N/C / 0.04 T
  • T = N s / (C m)
  • N/C / (N s / C m) = m / s
  • v = 3.0×104 m/s

Notes: Charge in uniform B field

Deflection
  • + charge is initially deflected upwards
  • Now that + charge is moving up / right, it is delfected up / left
  • Now that it is moving up, it is deflected left
  • ...
  • Deflection is always perpendicular to velocity
  • Because F is perpendicular to velocity, no work is done (v is constant)
  • → uniform circular motion
UCM due to B field
  • a = F / m = v2 / r
  • F = q v B
  • → q B / m = v / r
Example
  • Protons travel 3.0×104 m/s to the right.
  • They encounter a B field of .04 T into the board
  • Will they go clockwise, or counter clockwise? (counter clockwise)
  • How big is the circle they make? r = v m / (q B) = 7.97 mm